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1) 

Given: Quadrilateral DEFG is inscribed in circle P.

Prove: m∠D+m∠F=180º

 

2) 

 

3) Super Confused with this one...

 

4) 

Given: △ABC, DE¯∥AC¯

Prove: DA/BD=EC/BE

 

5)  derive a formula for the area of the triangle.

 

6) 

Given: NQ¯ is an altitude of △MNP.

Prove: sinM/m=sinP/p

 

 

Thank You So Much For ALL Of Your Help!!!!!!!!!!!! Thank you thank you thank you!!!!!!

KennedyPape  May 15, 2018
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1+0 Answers

 #1
avatar+86643 
+1

1. Opposite angles in an inscribed quadrilateral are supplementary.....thus  angles  D  and F  sum to  180°

 

2. Correct  !!!

 

3. Don't know this one

 

4.Since DE is parallel to AC, DE splits the sides of triangle BAC proportionally.....this means that

DA/BD  = EC/BE

 

5. sin C  = h/a

   

   The other answers are correct  !!!

 

 

6. Definition of an altitude

    

psin M  = h  and msinP  = h

 

Substitution Property of Equality

 

sin M / m  = sin P / p

 

 

cool cool cool

CPhill  May 15, 2018

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