+327 1)
Given: Quadrilateral DEFG is inscribed in circle P.
Prove: m∠D+m∠F=180º
2) 
3) Super Confused with this one...
4)
Given: △ABC, DE¯∥AC¯
Prove: DA/BD=EC/BE
5) derive a formula for the area of the triangle.
6)
Given: NQ¯ is an altitude of △MNP.
Prove: sinM/m=sinP/p
Thank You So Much For ALL Of Your Help!!!!!!!!!!!! Thank you thank you thank you!!!!!!
+129852 1. Opposite angles in an inscribed quadrilateral are supplementary.....thus angles D and F sum to 180°
2. Correct !!!
3. Don't know this one
4.Since DE is parallel to AC, DE splits the sides of triangle BAC proportionally.....this means that
DA/BD = EC/BE
5. sin C = h/a
The other answers are correct !!!
6. Definition of an altitude
psin M = h and msinP = h
Substitution Property of Equality
sin M / m = sin P / p
