I figured out the answer but just need to know if I am right.
The nth term of a sequence is represented by 2n^4+25n^2+32n−15/6n^4+2n^3−11n^2−2n+17.
What is the limit of the nth term as x becomes increasingly large?
CORRECT !!!
Limit = 2/6 = 1/ 3 good job !!!
Thanks, CPhill! :)
+133 
