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In the figure, if FR = FG, the measure of arc FG is \(130^\circ\), and measure of arc FQ is \(28^\circ,\) then what is \(\angle RPG,\) in degrees?

 May 31, 2020
 #1
avatar+47 
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If \(FG\) = \(FR\), Arc \(FG\) = Arc \(FR\).    

\(FQ = 28°\) 

Total:

\(360-[2(130°)+28°]= \angle RPG\)

 

\(\angle RPG = 72\)

 May 31, 2020
 #2
avatar+1114 
+1

180º - 116º = 64º

 

Angle RPG = 64º  indecision

 

 Jun 1, 2020
edited by Dragan  Jun 1, 2020

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