Please explain very well in this question

Question

0

1002

2

Part (a): Find the sum $a + (a + 1) + (a + 2) + \dots + (a + n - 1)$ in terms of and

Part (b): Find all pairs of positive integers such that $n \ge 2$ and $a + (a + 1) + (a + 2) + \dots + (a + n - 1) = 100.$

Guest Jan 17, 2015

+23254

+5

Best Answer

Part a: There are n terms, so the sum of n terms of a is an.

The sum of the n terms: 0, 1, 2, 3, ..., n-1 = n(0 + n - 1)/2 = n(n - 1) / 2

The total sum is: an + n(n - 1)/2

geno3141 Jan 17, 2015

geno3141 · Answer 1 · 2015-01-17T05:36:09

Part a: There are n terms, so the sum of n terms of a is an.

The sum of the n terms: 0, 1, 2, 3, ..., n-1 = n(0 + n - 1)/2 = n(n - 1) / 2

The total sum is: an + n(n - 1)/2

Guest · Answer 2 · 2015-01-17T06:01:13

what about part b? Sorry