Find the domain and range of f(x) = sqrt(2x-5) / (x-3)
\(x-3\ne 0\rightarrow x\ne 3\). Also, \(2x-5\ge 0\rightarrow x\ge 5/2\). So domain is \(x\ge 5/2, x\ne 3\). For range, it is simply all reals.
+600 
