Ken has a six sided die. He rolls the die, and if the result is not even, he rolls the die one more time. Find the probability that he ends up with an even number.
If Ken rolls a 6 sided die once and get's an odd number, the probability decreases, giving us a probability of 3/4
the probability of first being even is:
1/2 or 50 % since half of the numbers are even
the probability of first being odd and second being even is:
1/2*1/2=1/4 or 25%
there is a 75% (3/4 times) probability that either an even number will be on the first attempt or the second attempt