+0  
 
0
66
1
avatar+108 

If

 

   \(f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases} \)

 

then for how many values of \(x\) is \(f(f(x)) = 5\)?

 Aug 25, 2020
 #1
avatar
0

There are 3 values of x that work.

 Aug 25, 2020

13 Online Users

avatar