+0

0
66
1
+108

If

$$f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases}$$

then for how many values of $$x$$ is $$f(f(x)) = 5$$?

Aug 25, 2020

#1
0

There are 3 values of x that work.

Aug 25, 2020