If
\(f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases} \)
then for how many values of \(x\) is \(f(f(x)) = 5\)?
There are 3 values of x that work.
+109 
