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What is 3-x*2=2x^3

Guest Feb 24, 2017
 #1
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3-x*2=2x^3   rearrrange  as

 

2x^3 + x^2 - 3  =  0   and we can write

 

2x^3 - 2x^2  + 3x^2 - 3  = 0    this factors as

 

2x^2 ( x - 1) + 3(x^2 - 1)  = 0

 

2x^2 (x - 1) + 3 ( x + 1)(x - 1)  = 0

 

(x - 1) (2x^2  + 3 (x + 1 )   = 0

 

(x - 1) (2x^2 + 3x + 3)  = 0

 

Settng the first factor to 0 and the one real root is x = 1

 

The other two roots are non-real  (complex)

 

 

cool cool cool

CPhill  Feb 24, 2017

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