#1**0 **

3-x*2=2x^3 rearrrange as

2x^3 + x^2 - 3 = 0 and we can write

2x^3 - 2x^2 + 3x^2 - 3 = 0 this factors as

2x^2 ( x - 1) + 3(x^2 - 1) = 0

2x^2 (x - 1) + 3 ( x + 1)(x - 1) = 0

(x - 1) (2x^2 + 3 (x + 1 ) = 0

(x - 1) (2x^2 + 3x + 3) = 0

Settng the first factor to 0 and the one real root is x = 1

The other two roots are non-real (complex)

CPhill
Feb 24, 2017