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Terry and Tao are canoeing on a lake that is 2000 meters across from the west side of the lake to the east side. Terry rows at 60 meters per minute and Tao rows at 40 meters per minute. Terry starts rowing at 2 PM from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 PM. If they always row directly towards each other, at what time will the two meet?

Sep 15, 2018

#1
+18280
+2

Terry gets a 5 minute head start and covers 5 min x 60 m/min = 300 m

then Tao starts at 1405       They have  2000 - 300 = 1700 meters to cover before they meet

the distance is closing at (40+60)= 100 m/min

1700 m  / (100 m/min) = 17 minutes after Tao starts   14:05 + 17 = 14:22    (02:22 PM)

(corrected...THANX!)

Sep 15, 2018
edited by ElectricPavlov  Sep 16, 2018
#2
+1

Let the time taken by Terry=T
Time taken by Tao =T - 5
60T + 40(T - 5) =2,000
60T + 40T - 200=2,000
100T =2,200
T = 22 minutes after 2 pm when they will meet.
Note: EP made a typo of 23 minutes.

Sep 15, 2018