how does this work, (2/3)^-3
\(\small{ \begin{array}{rcl} \left(\dfrac23 \right)^{-3} &=& \left(\dfrac32 \right)^{3}\\\\ &=& \dfrac{27}{8} \\ \mathbf{ \left(\dfrac23\right)^{-3} } &\mathbf{=}& \mathbf{3.375} \end{array} }\)
=3 3/8
