Let f(x)=6(2)x−1+4 .

The graph of f(x) is stretched vertically by a factor of 4 to form the graph of g(x) .

What is the equation of g(x)

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g(x) =

g(x) = 4 * f(x)

= 4 * ( 6(2)x − 1 + 4 )

= 4 * ( 12x + 3 )

= 48x + 12

Thanks, hectictar...... !!!!

I think this could also be :

f(x) = 6(2)^{x - 1 } + 4

4f(x) = g(x)

4 [ 6(2)^{x - 1 } + 4 ] =

24(2)^{x - 1 } + 16 = g(x)

THANK YOU BOTH!!!!