We flip a fair coin 10 times. What is the probability that we get heads in at least 6 of the 10 flips?
The probability of AT LEAST 6 heads: [10C0 + 10C1 + 10C2 + 10C3 + 10C4] / 2^10 =
[1 + 10 + 45 + 120 + 210] / 1024 = 386 / 1024 =~37.7%
+194 
