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We flip a fair coin 10 times. What is the probability that we get heads in at least 6 of the 10 flips?

 Feb 25, 2018
edited by Maplesnowy  Feb 25, 2018

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The probability of AT LEAST 6 heads: [10C0 + 10C1 + 10C2 + 10C3 + 10C4] / 2^10 =

[1 + 10 + 45 + 120 + 210] / 1024 = 386 / 1024 =~37.7%

 Feb 25, 2018
 #1
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Best Answer

The probability of AT LEAST 6 heads: [10C0 + 10C1 + 10C2 + 10C3 + 10C4] / 2^10 =

[1 + 10 + 45 + 120 + 210] / 1024 = 386 / 1024 =~37.7%

Guest Feb 25, 2018

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