#1**+2 **

Not that great at this either, RP...but...I think I can do a few

We have 6 * 4 = 24 possible outcomes.....here is the sample space :

Sum = (a, b) = (result of 4-sided die, result of 6-sided die )

2 = (1,1)

3 =(1,2) (2,1)

4 = (1,3) (3,1) (2,2)

5 = (1,4) (4,1) (2,3) (3,2)

6 = (2,4) (4,2) (3,3) (1,5)

7 = (2,5) (1,6) (3,4) (4,3)

8 = (4, 4) (3,5) (2,6)

9 = (4,5) (3,6)

10 = (4,6)

P(A)= the six-sided die is 3 ....

We have the following possibilities ...... (1,3) (2,3) (3,3) (4,3)

So P(A) = 4/24 = 1/6

P(B)= sum of the dice is 5 or less = 10 possibilities

So P(B) = 10/24 = 5/12

P (A l B) = Probability the six-sided die is 3, given that the sum of the die is 5 or less

If we let the first number represent the result of the 4 sided die and the second number the result of the 6-sided die, we have the following possibilites (1,3) and (2,3) = 2 possibilities

And the number of results l of 5 or less = 10 possibilities

So P (A l B) = 2/10 = 1/5

P(B l A) = Probability that the sum of the dice is 5, given that the six-sided is 3

We have the following possibilites for the six-sided die = 3

(1,3) (2,3) (3,3) (4,3) = 4 possibilities

Notice that there's only one thing that sums to 5 ⇒ (2,3)

So P(B l A) = 1 / 4

P (A and B ) = Probabilitiy that six-sided die is 3 and the sum of the die is 5 or less

Note : P(A and B) = P(A) * P(B) = (1/6) * (5/12) = 5 / 72

P(A) * P (B l A) = (1/6) * (1/4) = 1/24

P (B) * P( A l B) = (5/12) * (1/5) = 1/12

CPhill
Apr 4, 2018

#2**-1 **

Darn it was wrong but thanks for helping tho

P (A)=1/6

P (B)=5/12

P(A|B)=1/5

P(B|A)=1/2

P (A and B)=1/12

P (A)*P(B|A)=1/12

P(B)*P(A|B)=1/12

RainbowPanda
Apr 4, 2018