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2 Apr 4, 2018

#1
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Not that great at this either, RP...but...I think I can do a few

We have  6 * 4  = 24 possible outcomes.....here is the sample space :

Sum  = (a, b)  =  (result of 4-sided die, result of 6-sided die )

2 = (1,1)

3 =(1,2) (2,1)

4 = (1,3) (3,1) (2,2)

5 = (1,4) (4,1) (2,3) (3,2)

6 = (2,4) (4,2) (3,3) (1,5)

7 = (2,5) (1,6) (3,4) (4,3)

8 = (4, 4)  (3,5) (2,6)

9 = (4,5) (3,6)

10 = (4,6)

P(A)=   the six-sided die is 3  ....

We have the following possibilities  ......    (1,3) (2,3) (3,3) (4,3)

So P(A)  =  4/24   = 1/6

P(B)=  sum of the dice is 5  or less  = 10 possibilities

So  P(B)  =  10/24  = 5/12

P (A  l B)  =  Probability the six-sided die is 3, given that the sum of the die is 5 or less

If we let  the first number represent the result of the 4 sided die  and the second number the result of the 6-sided die, we have the following possibilites  (1,3)  and (2,3)  = 2 possibilities

And the number of results l of 5 or less = 10 possibilities

So  P (A l  B)  =     2/10   = 1/5

P(B l A)  =  Probability that the sum of the dice  is 5, given that the six-sided is 3

We have the following possibilites for the six-sided die  = 3

(1,3) (2,3)  (3,3)  (4,3) = 4 possibilities

Notice that  there's only one thing that sums to 5  ⇒  (2,3)

So  P(B l A)  =  1 / 4

P (A and B )  = Probabilitiy  that six-sided die is 3 and the sum of the die  is 5 or less

Note : P(A  and B)   = P(A) * P(B)  = (1/6)  * (5/12)   =   5 / 72

P(A)  * P (B l A)  =  (1/6) * (1/4)  =  1/24

P (B) * P( A l B)  =  (5/12) * (1/5)  =  1/12   Apr 4, 2018
edited by CPhill  Apr 4, 2018
#2
-1

Darn it was wrong but thanks for helping tho

P (A)=1/6

P (B)=5/12

P(A|B)=1/5

P(B|A)=1/2

P (A and B)=1/12

P (A)*P(B|A)=1/12

P(B)*P(A|B)=1/12

RainbowPanda  Apr 4, 2018