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Find all values of x such that 3x^2 14x 8 = 0. If you find more than one value, then list your solutions, separated by commas.

 Jul 7, 2023
 #1
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We can factor the quadratic equation 3x^2 + 14x + 8 as follows:

(3x + 2)(x - 4) = 0

This means that either 3x + 2 = 0 or x - 4 = 0. Solving for x in each case, we get x = -4/3 or x = 4. Therefore, the solutions to the equation 3x^2 + 14x + 8 = 0 are x = -4/3, 4.

 Jul 7, 2023
 #2
avatar+833 
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Find all values of x such that 3x^2 14x 8 = 0. If you find more than one value, then list your solutions, separated by commas.   

 

My monitor isn't displaying the signs between terms.   

I'm assuming that they should have been plus signs.  

 

Like this

                                                   3x2 + 14x + 8 = 0    

Factor the equation   

                                                   (3x + 2)(x + 4) = 0   

Set each factor = zero    

                                                   3x + 2 = 0   which means   x = –3/2   

                                                     x + 4 = 0   which means   x = –4    

Separated by commas   

                                                     x =    (–3/2, –4)    

If the polarity of 14x was       

supposed to be negative,     

and polarity of 8 positive,    

then change the minuses   

in the answer to pluses.                 

.

 Jul 7, 2023
 #3
avatar+833 
0

 

CORRECTION to my above.  

 

3x + 2 = 0 which means x = –3/2   

 

It should have been      x = –2/3     

 

Which makes the final answer     x  =  (–2/3, –4) 

.

Bosco  Jul 17, 2023

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