Ok so I think the form is ax^2+bc+c
So, 2x^2-3x+3
I did not think that this could be factored, so I am using the quadratic equation:
(-b+-sqrt(b^2-4ac))/2a
(3+-sqrt(9-4(2)(3)))/4
(3+-sqrt(-15))/4
Sqrt(-15) can have "i" taken out because it's imaginary.
(3+-isqrt(15))/4
answer 1: (3+i sqrt(15))/4
answer 2: (3-i sqrt(15))/4
I hope this is actually correct.