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Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)

 Aug 28, 2020
 #1
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The line is y = 3/2*x - 1.

 Aug 28, 2020
 #2
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Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)

 

Rewrite the equation as  y = (2/3)x - 4  This has slope 2/3

 

A perpendicular line will have slope -3/2 so the equation of a perpendicuar line is y = -(3/2)x + c where c is a constant found from the fact that the line must go through point (16, -7).

 

-7 = -(3/2).16 + c

c = 24 - 7 

c = 17

 

Hence perpendicular line has equation  y = -(3/2)x + 17

 Aug 28, 2020

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