Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)
+33614 Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)
Rewrite the equation as y = (2/3)x - 4 This has slope 2/3
A perpendicular line will have slope -3/2 so the equation of a perpendicuar line is y = -(3/2)x + c where c is a constant found from the fact that the line must go through point (16, -7).
-7 = -(3/2).16 + c
c = 24 - 7
c = 17
Hence perpendicular line has equation y = -(3/2)x + 17
