Tried solving it but pretty sure i'm doing something wrong help plz
This is a classic example of system of equations.
If x represented the number of people in a bus,
and y the number of people in a van, we can write the equations:
6y + x = 146 --- (1)
12y + 8x = 592 --- (2)
1) Substitution
In (1), we can subtract 6y from both sides.
x = 146 - 6y, which we can substitute into (2).
12y + 8(146 - 6y) = 592. Then after solving for y, we can plug into (1) to solve for x.
I understand, somewhat. I knew how to do that part but not what comes after..
8*146 and 8*6
12V+1168-48V=592
(I'm using V and B i hope that's okay!)
Then what do I do next with the 12V and 48V?
Let x be the number of people in each van and y be the number of people in each bus....and we have that
6x + 1y = 146 rearrange as 1y = 146 - 6x ⇒ y = 146 - 6x (1)
12x + 8y = 592 (2)
Put (1) into (2) for "y" and we have
12x + 8(146 - 6x) = 592 simplify
12x + 1168 - 48x = 592
-36x + 1168 = 592 subtract 1168 from both sides
-36x = -576 divide both sides by -36
x = 16 ⇒ number of students in each van
Amd using (1)...the number of students in each bus is 146 - 6(16) = 146 - 96 = 50
You are correct, RP!!!