+0

+1
214
4
+2448

Tried solving it but pretty sure i'm doing something wrong help plz

Sep 3, 2018

#1
+974
+1

This is a classic example of system of equations.

If x represented the number of people in a bus,

and y the number of people in a van, we can write the equations:

6y + x = 146 --- (1)

12y + 8x = 592 --- (2)

1) Substitution

In (1), we can subtract 6y from both sides.

x = 146 - 6y, which we can substitute into (2).

12y + 8(146 - 6y) = 592. Then after solving for y, we can plug into (1) to solve for x.

Sep 3, 2018
#2
+2448
+1

I understand, somewhat. I knew how to do that part but not what comes after..

8*146 and 8*6

12V+1168-48V=592

(I'm using V and B i hope that's okay!)

Then what do I do next with the 12V and 48V?

RainbowPanda  Sep 3, 2018
edited by RainbowPanda  Sep 3, 2018
#3
+2448
0

I got V=16 and B=50 just gonna go with that

Sep 3, 2018
#4
+100516
+1

Let x be the number of people in each van and y  be the number of people in each bus....and we have that

6x  + 1y  = 146    rearrange as   1y  = 146  - 6x  ⇒   y  =  146  - 6x    (1)

12x + 8y  = 592     (2)

Put  (1)  into (2)  for  "y"  and we have

12x  + 8(146  - 6x)  = 592    simplify

12x + 1168  - 48x   = 592

-36x  + 1168  = 592   subtract  1168 from both sides

-36x  = -576    divide both sides by -36

x  = 16  ⇒   number of students in  each van

Amd using  (1)...the number of students in each bus is  146  - 6(16)  =  146  - 96  =  50

You are correct, RP!!!

Sep 4, 2018