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A ball is thrown in the air from a platform that is 48 feet above the ground with an initial vertical velocity of 32 feet per second. The height of the ball, in feet, can be represented by the function h(t) = -16t^2 +32t +48, where t is the time, in seconds, since the balls was thrown. How long does it take the ball to hit the ground?

 Jan 12, 2021
edited by Guest  Jan 12, 2021
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-16t^2  +  32t +  48  =  0            divide through by   -16

 

t^2   - 2t  - 3   =  0                      factor

 

(t - 3)  ( t + 1)  =  0

 

t  - 3   =  0

 

t  = 3 seconds

 

 

cool cool cool

 Jan 12, 2021

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