+0  
 
+2
422
4
avatar+46 

I need help with this problem

 May 1, 2021
 #1
avatar+2407 
+2

We can't see the problem. 

 

=^._.^=

 May 1, 2021
 #2
avatar+46 
+1

Sorry

faultypancake  May 1, 2021
 #3
avatar+2407 
+1

 ORQ is an equilateral triangle, with the sides being the raduis. 

pi r^2 = 48pi

r = 4sqrt(3)

Now, the circumcenter is the right angle of the lines to the angle. 

Can you solve it from here?

 

=^._.^=

catmg  May 1, 2021
 #4
avatar
0

A = (√3)/4 [2(sin15º * √48)]2

 May 1, 2021

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