+0  
 
0
34
1
avatar+8 

I honestly don't even know where to start.

 Jan 14, 2019

Best Answer 

 #1
avatar+97599 
+2

Just replace the x with 3

 

\(f(3)=\frac{20}{4+3e^{-0.2*3}}\\ f(3)=\frac{20}{4+3e^{-0.6}}\\\)

 

20/(4+3e^-0.6) approx = 3.5420580109166572

 Jan 14, 2019
 #1
avatar+97599 
+2
Best Answer

Just replace the x with 3

 

\(f(3)=\frac{20}{4+3e^{-0.2*3}}\\ f(3)=\frac{20}{4+3e^{-0.6}}\\\)

 

20/(4+3e^-0.6) approx = 3.5420580109166572

Melody Jan 14, 2019

12 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.