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If $f(c)=\frac{3}{2c-3}$, find $\frac{kn^2}{lm}$ when $f^{-1}(c)\times c \times f(c)$ equals the simplified fraction$\frac{kc+l}{mc+n}$, where $k,l,m,\text{ and }n$ are integers.

 Jul 31, 2021
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(kn^2)/(lm) = (6*2^2)/(2*1^2) = 12.

 Jul 31, 2021

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