\(I\) is the incenter of \(\triangle ABC.\). We have \(CE = 12\), \(AE = 9\), and \(AB = 12.\) Find \(BC.\)
https://latex.artofproblemsolving.com/7/f/4/7f44a10a26ba1dea8f8b075f1d8c5e463ef1d307.png
From the angle bisector theorem, BC = 18.
Unfortunately, I don't think that is correct. Could you please reconsider? Thank you for your time.
Using the angle bisector theorem we have: AE : EC = AB : BC
9 / 12 = 12 / BC BC = 16
