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\(I\) is the incenter of \(\triangle ABC.\). We have \(CE = 12\)\(AE = 9\), and \(AB = 12.\) Find \(BC.\)

 

https://latex.artofproblemsolving.com/7/f/4/7f44a10a26ba1dea8f8b075f1d8c5e463ef1d307.png

 Nov 14, 2020
edited by Guest  Nov 14, 2020
 #1
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From the angle bisector theorem, BC = 18.

 Nov 14, 2020
 #2
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Unfortunately, I don't think that is correct. Could you please reconsider? Thank you for your time.

Guest Nov 14, 2020
 #3
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Using the angle bisector theorem  we have: AE : EC = AB : BC

 

9 / 12 = 12 / BC          BC = 16

 Nov 15, 2020

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