Let \(ABCD\) be a trapezoid with bases \(\overline{AB}\) and \(\overline{CD}\). Let \(AD=5\) and \(BC=7\) and let \(P\) be a point on the side \(\overline{CD}\) such that \(\frac{CP}{PD}=\frac{7}{5}.\) Let \(X, Y\) be the feet of the altitudes from \(P\) to \(\overline{AD},\overline{BC}\) respectively. Show that \(PX=PY.\)
(There was no image for this problem.)
Thank you!
Please do not discuss this problem! This is an active homework problem.
To the original poster: I realize that homework may be challenging. If you wish to receive some help from the staff or other students, I encourage you to use the resources that the online classes provide, such as the Message Board. Thanks.
