web2.0calc
 
+0  
 

Please Help - GEOMETRY

0
150
2
avatar+24 

In the diagram below, we have \(\overline{AB}\parallel\overline{CD}\),\(QP = QR\) ,\(\angle BPQ = x^\circ + 100^\circ\) , and \(\angle APR = x^\circ\). Find \(x\).

https://latex.artofproblemsolving.com/2/3/6/23637a6b4f6218e50583ee5b39bcc517771d75a8.png
 

 Feb 5, 2023

2+0 Answers

 #1
avatar
0

x = 144/5

 Feb 5, 2023
 #2
avatar
0

Angle APR==Angle PRQ ==x


Angle PRQ ==Angle QPR==x  {Because triangle PQR is an isosceles triangle}


Angle BPQ ==Angle PQR ==100 + x 


From isosceles triangle PQR, we have:


(100 + x) + x + x ==180


3x ==180 - 100 ==80 


x ==80 / 3 ==26 + 2/3 == 26.6667 degrees

 Feb 5, 2023

3 Online Users

avatar

Top Users

avatar+129881 CPhill moderator
avatar+118679 Melody moderator
avatar+33661 Alan moderator
avatar+15000 asinus moderator
avatar+2489 GingerAle
avatar+1926 NotThatSmart
avatar+1557 parmen
avatar+1459 blackpanther
avatar+1439 kittykat
avatar+1277 Bosco
avatar+1274 learnmgcat

Sticky Topics