The line \(y = \frac{3x + 15}{4}\) intersects the circle \(x^2 + y^2 = 36\) at \(A\) and \(B\). Find the length of chord \(\overline{AB}\).
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Find the points of intersection of the line y = (3x + 15)/4 and the circle x2 + y2 = 36
and then determine the distance between them.
First, using substitution to find the points: x2 + [ (3x + 15)/4 ]2 = 36
x2 + (9x2 + 90x + 225)/16 = 36
16x2 + 9x2 + 90x + 225 = 576
25x2 + 90x - 351 = 0
Using the quadratic formula to find the values for x:
x1 = ( -90 + sqrt( 43200 ) ) / 50
x2 = ( -90 - sqrt( 43200 ) ) / 50
Substitue each value of x into the equation y = (3x + 15)/4 to get its corresponding y-value.
Then, use the distance formula to find the distance between these two points.