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Henry spent 3/8 of his money on a badminton racket. He spent 1/8 of his money on a watch. The badminton racket cost $14 more than the watch. How much money did Henry spend on the two items altogether? Sep 14, 2021 ### 3+0 Answers #1 +36416 0 3/8 ths x on racket - 1/8x on watch = 14 3/8 x - 1/8 x = 14 2/8 x = 14 x = 14 * 8/2 = 14 * 4 = 56 dollars initially (3/8 + 1/4) 56 = 35 dollars total Sep 17, 2021 #2 +13571 +1 How much money did Henry spend on the two items altogether? Hello Guest! Henry owns x. $$\color{blue}\frac{x}{8}+14=\frac{3x}{8}\\ \frac{3x-x}{8}=14\\ 2x=112$$ $$x=56$$ $$(\frac{1}{8}+\frac{3}{8})\cdot 56=\color{blue}28$$$28 did Henry spend on the two items altogether.

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Sep 17, 2021
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Straightforward. First, assign variables to the unknown values:

Let H = Henry’s money
Let W = Watch

We are given:
B = 3/8 H
W = 1/8 H
B = W + $14 So: Substitute B and W: 3/8 H = 1/8 H +$14 [Cost of Badminton racket = $14 more than cost of watch] Solving: 3/8 H - 1/8 H =$14
(3/8–1/8) H = $14 2/8 H =$14
1/4 H= $14 H = 4 *$14 = $56 [Henry’s total money] B = 3/8 *$56 = $21 [Cost of badminton racket] W = 1/8 *$56 = $7 [Cost of watch] Check: B = W +$14
$21 =?$7 + $14 Yes! Henry spent B+W on his items altogether, which is$21+$7 =$28.

Another way of expressing it is:
2/8 H = $14 1/8 H =$7

B+W = 3/8 H + 1/8 H = (3+1)/8 H = 4/8 H = 1/2 H.
H = $56 B+W = 1/2 H =$28

Sep 17, 2021