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The current world population is about 7 billion. Under current conditions the population is growing exponentially with a yearly growth factor of 1.014. In parts (b) and (c), round your answers to the nearest year.

 

(a) Find a formula that gives the world population N, in billions, after t years.

 

(b) How long will it take the population to double?

 

 

(c) How long after doubling will it take for the population to double again?

 Nov 7, 2015

Best Answer 

 #3
avatar+130536 
+5

Sorry, Guest, I mis-read the question....the correct answer to (c) is, of course, about 50 years....!!!!

 

 

 

cool cool cool

 Nov 7, 2015
 #1
avatar+130536 
+5

(a) 

 

N  = N0 (1.014)t    where N0  is the initial population, t is in years and N is the population after t years

 

 

(b)

 

2N0  =N0 (1.014)t     divide through by N0

 

2  = (1.014)t        take the log of both sides

 

log 2  = log (1.014)t    and by a log property we can write

 

log 2  = t * log (1.014)     divide both sides by log(1.014)

 

log 2 / log 1.014    = t  = about 49.85 yrs = 50 yrs

 

 

(c)  If it doubles again, it is 4 times the original number, i.e., 4N0....and we can solve this :

 

log 4 / log 1.014  = t = about 99.71 yrs = 100 yrs

 

So......it takes about 50 years to double again

 

 

cool cool cool

 

Part (c) was edited for an original mistake......!!!!!!

 Nov 7, 2015
edited by CPhill  Nov 7, 2015
 #2
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+5

PART C is wrong :(

 Nov 7, 2015
 #3
avatar+130536 
+5
Best Answer

Sorry, Guest, I mis-read the question....the correct answer to (c) is, of course, about 50 years....!!!!

 

 

 

cool cool cool

CPhill Nov 7, 2015

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