Line \(L_1\) represent the graph of 3x + 4y = -14. Line \(L_2\) passes through the point (-5,7), and is perpendicular to line \(L_1\). If line\(L_2\) represents the graph of y=mx +b
, then find m+b.
+287 Linear function y = mx +b ,
y = (3/4) x -14 .....L1
Let m = slope of L1 = (3/4)
m2 = slope of L2
if the lines are perpendicular : slope ( m1 * m2 ) = ( - 1 )
(3/4) m2 = -(1) , m2 = (-1)* (4/3) = -(4/3)
Then L2: y = -(4/3)x + b.......L2
Find b: Plug in (x = -5, y = 7 ) into y = -(4/3)x +b.....L2
