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Line \(L_1\) represent the graph of 3x + 4y = -14. Line \(L_2\) passes through the point (-5,7), and is perpendicular to line \(L_1\). If line\(L_2\) represents the graph of y=mx +b
, then find m+b.

 Jun 13, 2021
 #1
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Linear function   y = mx +b   , 

y =  (3/4)  x -14   .....L1

Let  m = slope of L= (3/4)  

m2 =  slope of  L2

if the lines are perpendicular :     slope   ( m1 * m2 ) =  ( - 1 )   

   (3/4) m2   = -(1) ,     m2   =  (-1)* (4/3)  =   -(4/3)

Then L2:   y =  -(4/3)x + b.......L2

Find b:   Plug in (x = -5, y  = 7 ) into    y = -(4/3)x +b.....L2

 Jun 13, 2021
edited by Bginner  Jun 13, 2021

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