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avatar+32 

Plz help me to answer these 2 questions!

 Feb 9, 2019
 #1
avatar+59 
+2

Challenge 4:

x:6 = 5:3 because of parallel lines.

we can write this in fraction form and solve:

x/6=5/3

6(x/6)=6(5/3)

x=30/3=10

 

5:3=12:y

5/3=12/y

y(5/3)=y(12/y)

5y/3=12

3(5y/3)=3(12)

5y=36

y=36/5

 Feb 9, 2019
 #2
avatar+98090 
+2

(3a)

Note that angle CBD = angle CBA

And angle   CDB = angle BCA

So....by AA congruency, triangle BDC is similar to triangle BCA

 

 

(3b)

Note that angle CAB  =  angle CAD

And angle  ACB = angle  CDA

So....by AA congruency, triangle  ADC  is similar to triangle ACB

 

 

For the second one....it's easier to find y first

 

We have that   

12/5 = y/3      cross- multiply...

 

3*12 = 5*y 

 

36 = 5y      divide both sides by 5

 

36/5 = y = 7.2

 

And

 

[12 + 5 ] / x  = [y + 3 ] / 6

 

[ 17 ] / x = [ 7.2 + 3 ] / 6       cross-multiply

 

17*6  = 10.2 x  

 

102 = 10.2 x     divide both sides by 10.2

 

10 = x

 

 

cool cool cool

 Feb 9, 2019

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