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1. What is the simplest form of the radical expression √48x^4y^3

Thank you!! (I posted this a little over 45 minutes ago so im trying again <3)

Nov 20, 2018

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√[ 48x^4y^3 ]   = √16 *√3 * √x^4 *√y^3   =  4 * √3 * x^2  *y√y  =

4x^2y√ [ 3y]

Second one.....easiest way to do this is to  simplify top/bottom separately

1     +      2              [ y   + 2x^2]

__          __     =        ____________     (1)        and

x^2          y                    x^2y

5     -   6                   [ 5y^2 - 6x ]

__      ____    =      ___________        (2)

x         y^2                   xy^2

So we have    (1)   / (2)

Keep (1)   , invert (2)   and multiply

[ y + 2x^2]         [xy^2]

_________   *  _________     =

x^2y                [ 5y^2 - 6x]

[ y + 2x^2]        [ xy^2 ]

________    *  _______ =

[5y^2 - 6x ]       [x^2y]

[ y + 2x^2 ] *  [  y ]

_________   _____    =

[ 5y^2 - 6x]     [ x]

[ y^2 + 2x^2y ]

____________

[ 5xy^2 - 6x^2]

Nov 20, 2018
edited by CPhill  Nov 20, 2018