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Please help me<3

 

1. What is the simplest form of the radical expression √48x^4y^3

 

 

Thank you!! (I posted this a little over 45 minutes ago so im trying again <3)

 Nov 20, 2018
 #1
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√[ 48x^4y^3 ]   = √16 *√3 * √x^4 *√y^3   =  4 * √3 * x^2  *y√y  =  

 

4x^2y√ [ 3y]

 

 

Second one.....easiest way to do this is to  simplify top/bottom separately

 

1     +      2              [ y   + 2x^2]

__          __     =        ____________     (1)        and

x^2          y                    x^2y

 

 

5     -   6                   [ 5y^2 - 6x ]

__      ____    =      ___________        (2)

x         y^2                   xy^2

 

 

So we have    (1)   / (2)

 

Keep (1)   , invert (2)   and multiply

 

 

[ y + 2x^2]         [xy^2]

_________   *  _________     =

 x^2y                [ 5y^2 - 6x]

 

 

 

[ y + 2x^2]        [ xy^2 ]

________    *  _______ =

 [5y^2 - 6x ]       [x^2y]

 

 

[ y + 2x^2 ] *  [  y ]

_________   _____    =

[ 5y^2 - 6x]     [ x]

 

 

[ y^2 + 2x^2y ]

____________

[ 5xy^2 - 6x^2]

 

 

cool cool cool

 Nov 20, 2018
edited by CPhill  Nov 20, 2018

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