+73 A right triangle has legs of length $6$ and $b,$ and a hypotenuse of length $c$. The perimeter of the triangle is $18$. Compute $c$.
+73 I found the correct answer. Your answer is wrong but thanks for trying.
This is the explanation for the real answer :
Since the perimeter is $18$, $b+c=12$. Also, by the Pythagorean Theorem, $c^{2}-b^{2}=6^{2}$. Thus,
$36=c^{2}-b^{2}=(c-b)(c+b)=12(c-b)$
So $c-b=3$. Adding $b+c=12$ to this, we find $2c=15\Rightarrow c=\boxed{\frac{15}{2}}$.
+73 I found the correct answer. Your answer is wrong but thanks for trying.
This is the explanation for the real answer :
Since the perimeter is $18$, $b+c=12$. Also, by the Pythagorean Theorem, $c^{2}-b^{2}=6^{2}$. Thus,
$36=c^{2}-b^{2}=(c-b)(c+b)=12(c-b)$
So $c-b=3$. Adding $b+c=12$ to this, we find $2c=15\Rightarrow c=\boxed{\frac{15}{2}}$.
+1490 A right triangle has legs of length 6 and b and a hypotenuse of length c.The perimeter of the triangle is18.Compute c.
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a = 6 b = 6 / tanA c = sqrt[62 +(6 / tanA)2]
We'll use this information to calculate the angle A a + b + c = 18
6 + 6 / tanA + sqrt[62 + (6 / tanA)2] = 18 angle A = 53.13010235º
Side b = 6 / tanA = 4.5
Side c = sqrt(a2 + b2) = 7.5
