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This figure shows circle O with ​ diameter QS ​.

 

mRSQ=280∘

 

What is the measure of  ∠ROQ ?

Enter your answer in the box.

__°

​ Quadrilateral ABCD ​ is inscribed in circle O. 

What is ​ m∠C ​ ?

 

Enter your answer in the box.


___°

Guest Mar 2, 2018
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2+0 Answers

 #1
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+1

ROQ  =  measure of minor arc RQ  =   360  - (280)   =   80°

 

Second one.......since this is a cyclic quadrilateral......Angles B + D   = 180

 

So we have

 

(2x + 3) + (4x + 3)  = 180    simplify

 

6x + 6  =180  subtract 6 from both sides

 

6x  =  174     divide both sides by 6

 

x  =  29

 

So   ...C  = 2(29) + 1  =    59°

 

 

cool cool cool

CPhill  Mar 2, 2018
 #2
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Thank you so much @CPhill and i have two more qustion I'm about to post

Guest Mar 2, 2018

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