This figure shows circle O with diameter QS .
mRSQ=280∘
What is the measure of ∠ROQ ?
Enter your answer in the box.
__°
Quadrilateral ABCD is inscribed in circle O.
What is m∠C ?
Enter your answer in the box.
___°
+129918 ROQ = measure of minor arc RQ = 360 - (280) = 80°
Second one.......since this is a cyclic quadrilateral......Angles B + D = 180
So we have
(2x + 3) + (4x + 3) = 180 simplify
6x + 6 =180 subtract 6 from both sides
6x = 174 divide both sides by 6
x = 29
So ...C = 2(29) + 1 = 59°
