This figure shows circle O with diameter QS .

mRSQ=280∘

What is the measure of ∠ROQ ?

Enter your answer in the box.

__°

Quadrilateral ABCD is inscribed in circle O.

What is m∠C ?

Enter your answer in the box.

___°

Guest Mar 2, 2018

#1**+1 **

ROQ = measure of minor arc RQ = 360 - (280) = 80°

Second one.......since this is a cyclic quadrilateral......Angles B + D = 180

So we have

(2x + 3) + (4x + 3) = 180 simplify

6x + 6 =180 subtract 6 from both sides

6x = 174 divide both sides by 6

x = 29

So ...C = 2(29) + 1 = 59°

CPhill
Mar 2, 2018