Find the values of the trigonometric functions of t from the given information.
tan(t) = −5, csc(t) > 0
sin(t) =
cos(t) =
csc(t) =
sec(t) =
cot(t) =
Since the tangent is negatie and the csc is positive.... " t " must fall into the second quadrant
tan t = -5 / 1 = 5 / - 1 = y / x
We need to find r = √ [ x^2 + y^2] = √ [ (-1)^2 + 5^2 ] = √26
sin t = y / r = 5 / √26 = (5/26)√26
cos t = x / r = -1 / √26 = -√26/26
csc t = r / y = √26 / 5
sec t = r / x = √26 / - 1 = -√26
cot t = x / y = -1/5
And there you go !!!