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The sides of an isosceles triangle have lengths 2x + 4 and x + 8. The base has length 5x - 2  What is the area of the triangle?

 Sep 15, 2020
 #1
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2x+4=x+8 --> x=4. So the sides are 12,12, and 18. Drawing the altitude, by the pythagorean theorem, we have the height = sqrt(12^2-(18/2)^2)=sqrt(144-81)=sqrt(63)=3*sqrt(7). So the area is 27sqrt7

 Sep 15, 2020
 #2
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 Sep 15, 2020
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