+130511 n^2 - 9n + 18
We only need to find out where the "zeroes" of this polynomial are.
So setting it to 0 and factoring, we have
(n - 6) (n-3) = 0
So.......n=6 and n=3
Note that when n = 5, the polynomial's value = -2 and when n = 7, the polynomial's value is 4. And for all integers, n > 7, this polynomial is > 0.
So the largest integer that makes this polynomial negative is when n = 5. Note that n = 6 just makes the polynomial = 0, as we found !!!!!
+130511 n^2 - 9n + 18
We only need to find out where the "zeroes" of this polynomial are.
So setting it to 0 and factoring, we have
(n - 6) (n-3) = 0
So.......n=6 and n=3
Note that when n = 5, the polynomial's value = -2 and when n = 7, the polynomial's value is 4. And for all integers, n > 7, this polynomial is > 0.
So the largest integer that makes this polynomial negative is when n = 5. Note that n = 6 just makes the polynomial = 0, as we found !!!!!
