Please help me! This homework question seriously has me stumped.

Evaluate abs(3 b-9)+abs(-3-b^2)+2 b^3 where b = -3:
abs(3 b-9)+abs(-3-b^2)+2 b^3 = abs(-3 3-9)+abs(-3-(-3)^2)+(-3)^3×2

(-3)^2 = 9:
abs(-3×3-9)+abs(-3-9)+2×(-3)^3

3 (-3) = -9:
abs(-9-9)+abs(-3-9)+2×(-3)^3

-9-9 = -18:
abs(-18)+abs(-3-9)+2×(-3)^3

-3-9 = -12:
abs(-18)+abs(-12)+2×(-3)^3

(-3)^3 = (-1)^3×3^3 = -3^3:
abs(-18)+abs(-12)+2×-3^3

3^3 = 3×3^2:
abs(-18)+abs(-12)+2 (-3×3^2)

3^2 = 9:
abs(-18)+abs(-12)+2 (-3×9)

3×9 = 27:
abs(-18)+abs(-12)+2 (-27)

Since -18<=0, then abs(-18) = 18:
18+abs(-12)-27×2

Since -12<=0, then abs(-12) = 12:
18+12-27×2

2 (-27) = -54:
18+12+-54

18+12-54 = -24:
Answer: |-24