+1438 Find three consecutive odd integers such that eight more than the sum of the first two is equal to eleven less than three times the third. Find the THIRD number.
+600 If first is x-2, second is x, third is x+2. (x-2)+x+8=3(x+2)-11 --> 2x+6=3x-5 --> x=11. The third is 11+2=13
