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A pair of consecutive integers has the property that 8 times the lesser is more than 4 times the greater.

Find the least pair of integers with this property.

what I did was:

8x>4(x+1)

x=1

did I do this correct??

Guest Jan 11, 2018

edited by
Guest
Jan 11, 2018

edited by Guest Jan 11, 2018

edited by Guest Jan 11, 2018

#3**+2 **

Not QUITE correct Guest ....

8x > 4(x+1)

8x > 4x + 4

4x > 4

x > 1 Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2 and the other number is 3

ElectricPavlov Jan 11, 2018

#2**+1 **

If x = 1 then the left hand side is 8x1 → 8 and the right hand side is 4(1 + 1) → 8, so the left hand side is ** not **greater than the right hand side.

Alan Jan 11, 2018

#3**+2 **

Best Answer

Not QUITE correct Guest ....

8x > 4(x+1)

8x > 4x + 4

4x > 4

x > 1 Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2 and the other number is 3

ElectricPavlov Jan 11, 2018