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A pair of consecutive integers has the property that 8 times the lesser is more than 4 times the greater.
Find the least pair of integers with this property.

 

 

what I did was: 

8x>4(x+1) 

x=1

 

did I do this correct?? 

Guest Jan 11, 2018
edited by Guest  Jan 11, 2018
edited by Guest  Jan 11, 2018

Best Answer 

 #3
avatar+12266 
+2

Not QUITE correct Guest ....

 

8x > 4(x+1)

8x > 4x + 4

4x > 4

x > 1       Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2   and the other number is 3

ElectricPavlov  Jan 11, 2018
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2+0 Answers

 #2
avatar+26677 
+1

If x = 1 then the left hand side is 8x1 → 8 and the right hand side is 4(1 + 1) → 8, so the left hand side is not greater than the right hand side.

Alan  Jan 11, 2018
 #3
avatar+12266 
+2
Best Answer

Not QUITE correct Guest ....

 

8x > 4(x+1)

8x > 4x + 4

4x > 4

x > 1       Since it is an interger set we are looking for and 'x' must be greater than 1 ..... so 'x' = 2   and the other number is 3

ElectricPavlov  Jan 11, 2018

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