Please help me with my homework

I know 

If you have  a sample, someone can show you how it is done,.......

Ok, the problem I need solved is (4x+17)*(3x+2)

Multiply  4x  times each of the terms in the second factor...then multiply 17 times each of the terms in the second factor...

    then collect like terms:

4x*3x + 4x * 2  + 17 * (3x) + 17 * 2

12x^2  +  59x + 34                                  Just be careful when there is a negative sign involved!

thanks so much! It really helped me 

I thought I was done and apparently, I have a division problem. (x^2-5x+6)/((2x-1)+(x/2)) is the problem. 

Hey, DeathlyHallows!

It looks like you want to simplify $\frac{x^2-5x+6}{\textcolor{red}{2x-1+\frac{x}{2}}}$ . Let's transform all the terms in the denominator such that they all have common denominators; this way, we will be able to add them together. 

$\textcolor{red}{2x-1+\frac{x}{2}}\Rightarrow\textcolor{red}{\frac{4x}{2}-\frac{1}{2}+\frac{x}{2}}$

Notice that I have not changed the value of the expression; I just created a common denominator. Now, combine like terms. 

$\textcolor{red}{\frac{4x}{2}-\frac{1}{2}+\frac{x}{2}\\ \frac{5x}{2}-\frac{1}{2}\\ \frac{5x-1}{2}}$

Therefore, $\frac{x^2-5x+6}{2x-1+\frac{x}{2}}=\frac{x^2-5x+6}{\frac{5x-1}{2}}$ . Now, it is time to simplify. 

$\frac{x^2-5x+6}{\frac{5x-1}{2}}*\frac{2}{2}\\ \frac{2(x^2-5x+6)}{5x-1}\\ \frac{2(x-2)(x-3)}{5x-1}$

Even after I factored the numerator completely, I did not find any common factors present in both the numerator and the denominator, so this expression is already in simplest form.