+63 I forgot how to multiply polynomials and a problem that requires this skill showed up on my hw that it due tomorrow.
+37146 If you have a sample, someone can show you how it is done,.......
+37146 Multiply 4x times each of the terms in the second factor...then multiply 17 times each of the terms in the second factor...
then collect like terms:
4x*3x + 4x * 2 + 17 * (3x) + 17 * 2
12x^2 + 59x + 34 Just be careful when there is a negative sign involved!
+63 I thought I was done and apparently, I have a division problem. (x^2-5x+6)/((2x-1)+(x/2)) is the problem.
+2446 Hey, DeathlyHallows!
It looks like you want to simplify \(\frac{x^2-5x+6}{\textcolor{red}{2x-1+\frac{x}{2}}}\) . Let's transform all the terms in the denominator such that they all have common denominators; this way, we will be able to add them together.
\(\textcolor{red}{2x-1+\frac{x}{2}}\Rightarrow\textcolor{red}{\frac{4x}{2}-\frac{1}{2}+\frac{x}{2}}\)
Notice that I have not changed the value of the expression; I just created a common denominator. Now, combine like terms.
\(\textcolor{red}{\frac{4x}{2}-\frac{1}{2}+\frac{x}{2}\\ \frac{5x}{2}-\frac{1}{2}\\ \frac{5x-1}{2}}\)
Therefore, \(\frac{x^2-5x+6}{2x-1+\frac{x}{2}}=\frac{x^2-5x+6}{\frac{5x-1}{2}}\) . Now, it is time to simplify.
\(\frac{x^2-5x+6}{\frac{5x-1}{2}}*\frac{2}{2}\\ \frac{2(x^2-5x+6)}{5x-1}\\ \frac{2(x-2)(x-3)}{5x-1}\)
Even after I factored the numerator completely, I did not find any common factors present in both the numerator and the denominator, so this expression is already in simplest form.
