Find all x so that 8x^2 * 4x = 2. Enter all the solutions, separated by commas.
+208 Hey there!
This can be altered using exponential laws like so:
\(2^{3x^{2}+2x}=2\)
Taking the logarithm of both sides produces the following.
\(3x^2+2x=1\)
\(3x^2+2x-1=0\)
From this, use the quadratic formula (\(x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\)), where \(a=3\), \(b=2\), \(c=-1\). This will give you the two \(x\) values you are looking for!
Let me know how you get on :)
