Point A is the terminal point of \(\phi \) and point B is the terminal point of \(\theta\) . Point A is in the first quadrant and point Bis in the second quadrant, while \(\tan \phi = 1\) and \(\tan \theta = -7\). Find the slope of AB.
Assuming these terminal points are on the unit circle:
arctan 1 = 45 degrees x = sqrt 2 /2 y = sqrt 2/2
arctan -7 = 98.13 degrees x = 1 cos 98.13 y = 1 sin 98.13
Now you have two x 's and two y 's slope = (y1-y2) / (x1-x2)