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Point A is the terminal point of \(\phi \) and point B is the terminal point of \(\theta\) . Point A is in the first quadrant and point Bis in the second quadrant, while \(\tan \phi = 1\) and \(\tan \theta = -7\). Find the slope of AB.

 Jun 6, 2020
 #1
avatar+24891 
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Assuming these terminal points are on the unit circle:

 

arctan 1  = 45 degrees                      x = sqrt 2 /2      y = sqrt 2/2

arctan -7 = 98.13 degrees                 x = 1 cos 98.13    y = 1 sin 98.13

 

 

Now you have two x 's  and two y 's      slope  =   (y1-y2) / (x1-x2)

 Jun 6, 2020
 #2
avatar+110 
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thank you so much!

littlemixfan  Jun 6, 2020

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