please help me

Since triangle(PQR) is an isosceles triangle, T will be the midpoint of PR; thereore, PT = 0.7 m

Also, QT bisects angle(PQR) so angle(PQT) = 19^o.

sin(19^o) = 0.7 / PQ   --->   PQ  =  0.7 / sin(19^o)   --->   PQ  =  .....

 

angle PQR is 38^o so angle PQT is half of that, or 19^o  

 

since angle PQT is 19^o that means angle QPT is 71^o 

 

PT is half of 1.4 m, or 0.7 m 

 

 0.7 m

———  =  cosine 71^o  

  PQ 

 

             0.7 m            0.7 m

PQ  =  ——–—  =  ——–——  =  2.1500 m rounded to two decimal places is 2.15 m 

           cos 71^o        0.32557