Moe can drive his car 450 mi. using 15 gal. of gas @ a steady pace. What is the # of mi. he can drive on 1,2,3,4,5,6,7,8,9 and 10 gal. of gas?
Here is how you would solve your question. I'll do the first 3
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{1}}}}$$ To solve for n, you start with your 450 and multiply it to the number diagonal to it. Here, we find that it is 1. After we multiply, we would then divide the number underneath the 450 you started with. Hence, we divide 450 by 15 and, in this case, n would equal 30, therefore meaning Moe can drive his car thirty miles with one gallon of gas.
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{2}}}}$$ (450*2=900 900/15=60)This time, he could travel sixty miles with two gallons of petro.
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{3}}}}$$ (450*3=1,350 1,350/15=90) With this one, we can see that Moe could travel ninety miles with three gallons of gasoline.
Hope this helps. Good luck!
Here is how you would solve your question. I'll do the first 3
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{1}}}}$$ To solve for n, you start with your 450 and multiply it to the number diagonal to it. Here, we find that it is 1. After we multiply, we would then divide the number underneath the 450 you started with. Hence, we divide 450 by 15 and, in this case, n would equal 30, therefore meaning Moe can drive his car thirty miles with one gallon of gas.
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{2}}}}$$ (450*2=900 900/15=60)This time, he could travel sixty miles with two gallons of petro.
$${\frac{{\mathtt{450}}}{{\mathtt{15}}}} = {\frac{{\mathtt{n}}}{{\mathtt{3}}}}$$ (450*3=1,350 1,350/15=90) With this one, we can see that Moe could travel ninety miles with three gallons of gasoline.
Hope this helps. Good luck!
