Quadrilateral ABCD is inscribed in circle O.
What is m∠C ?
m∠B + m∠D = 180º
Substitute.
(2x + 3) + (4x + 3) = 180º
Combine like terms.
6x + 6 = 180
6x = 174
x = 29
Now that we know what x is, we can find m∠C
m∠C = 2x + 1
m∠C = 2(29) + 1
m∠C = 58 + 1
m∠C = 59º
