+0  
 
0
195
1
avatar

Find a non-zero value for \(ax^2+8x+4=0\) such that  has only one solution.

Guest Dec 26, 2017
 #1
avatar+89876 
+2

ax^2 + 8x  +  4  = 0

 

This will only have one solution when the discriminant  = 0

 

So.....

 

8^2  -   4a(4)  = 0

 

64  - 16a  =   0     add 16a to both sdes

 

64  = 16a      divide both sides by 16

 

4  =  a

 

 

cool cool cool

CPhill  Dec 26, 2017

6 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.