+0  
 
0
116
1
avatar

Find a non-zero value for \(ax^2+8x+4=0\) such that  has only one solution.

Guest Dec 26, 2017
Sort: 

1+0 Answers

 #1
avatar+85757 
+2

ax^2 + 8x  +  4  = 0

 

This will only have one solution when the discriminant  = 0

 

So.....

 

8^2  -   4a(4)  = 0

 

64  - 16a  =   0     add 16a to both sdes

 

64  = 16a      divide both sides by 16

 

4  =  a

 

 

cool cool cool

CPhill  Dec 26, 2017

26 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details