Find a non-zero value for \(ax^2+8x+4=0\) such that has only one solution.
ax^2 + 8x + 4 = 0
This will only have one solution when the discriminant = 0
So.....
8^2 - 4a(4) = 0
64 - 16a = 0 add 16a to both sdes
64 = 16a divide both sides by 16
4 = a