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Find a non-zero value for \(ax^2+8x+4=0\) such that  has only one solution.

 Dec 26, 2017
 #1
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ax^2 + 8x  +  4  = 0

 

This will only have one solution when the discriminant  = 0

 

So.....

 

8^2  -   4a(4)  = 0

 

64  - 16a  =   0     add 16a to both sdes

 

64  = 16a      divide both sides by 16

 

4  =  a

 

 

cool cool cool

 Dec 26, 2017

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