Find the values of the trigonometric functions of t from the given information.
sec(t) = 6,
terminal point of t is in Quadrant IV
sin(t) =
cos(t) =
tan(t) =
csc(t) =
cot(t) =
+128475 sec = r / x ...so r = 6 and x = 1
We need to find y......since this angle is in the 4th quadrant, y will be negative
So y = - √ [ r^2 - x^2 ] = - √[ 6^2 - 1^2 ] = - √35
sin (t) = y / r = -√35 / 6
cos (t) = x / r = 1 / 6
tan (t) = y / x = -√35 / 1 = -√35
csc (t) = r / y = 6 / -√35 = ( -6/ 35)√35
cot (t) = x / y = 1 / -√35 = -1/√35 = -√35 / 35
