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Find the values of the trigonometric functions of t from the given information.

sec(t) = 6,

 terminal point of t is in Quadrant IV

sin(t) = 

 

 cos(t) = 

 

 tan(t) = 

 

 csc(t) = 

 

 cot(t) = 

Guest Apr 25, 2018
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sec =  r / x   ...so    r  = 6  and  x  = 1

 

We need to find y......since this angle is in the 4th quadrant, y will be negative

 

So  y  =  - √  [ r^2 - x^2 ] =  - √[ 6^2 - 1^2 ]  =  - √35

 

 sin (t)  =  y / r  = -√35 / 6

cos (t)  = x / r  = 1 / 6

tan (t)  =  y / x   =   -√35 / 1  = -√35

csc (t)  = r  / y  =  6 / -√35  =  ( -6/ 35)√35 

cot (t)  =  x / y  = 1 / -√35  =   -1/√35  =  -√35 / 35

 

 

cool cool cool

CPhill  Apr 25, 2018

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