The ratio of the number of brownies sold to the number of cookies sold is 3: 5.
Each piece of brownie was sold for $1 more than each piece of cookie. Eric
collected $154 for all brownies and cookies sold. He collected $44 more from the
sale of brownies than the sale of cookies. How many brownies were sold?
Let x = number of brownies sold.
y = number of cookies sold.
: x/y = 3/5
=> 5x - 3y = 0 -------- 1
Let $p be the price of each piece of cookies.
Given that, each piece of bro is sold for $1
more than each piece of cookie.
: The price of each piece of brownie is $(8+1)
Eric collected $154 for all brownies and cookies sold.
: (8+1)x + Py = 154 -------- 2
Also, Eric collected $44 more from the sale of brownies than the sale of cookies.
: (p+1)x = 44 + py
Substituting (p+1) x = 44+py in equation 2 we, get
44 + py + py = 154
=> 2py = 110
=> py = 55 ------ 3
From equation 1, y = 5/3x.
: Substituting value y = 5/3x in equation 3, we get
P(5/3x) = 55 => px = \({55 * 3 \over 5} = 33{}{}\)
=> px * 33 -----4
Substituting values of px = 33 of py = 55 in
equation 2, we have
(P+1)x + Py = 154
=> Px + x + Py = 154
=> 33 + x + 55 = 154 => x = 154 - 33 - 55
=> x = 66
Substituting x = 66 in equation 1, we have
5x - 3y = 0 => 5(66)- 3y = 0 => 3y = 330
=> y = 110
Substituting x = 66 in equation 4, we have
px = 33 => p (66) = 33 => P=0.5
: Each piece of cookie is sold at $0.5 and each piece of brownie is sold at $1.5
The number of cookie sold = y = 110.
The number of brownies sold is x = 66.
: 66 pieces of brownies were sold.