AB = 20 cm, the measure of A = 30 degrees, and the measure of C = 45 degrees. Express the number of centimeters in the length of BC in simplest radical form.
Any help would be greatly appreciated. 
+37146 Using law of sines
20/sin45 = BC/sin 30
sin30 * 20/sin45 = BC
1/2 * 20/(sqrt2/2) =
10 * 2/ sqrt2 20/ sqrt2 = 20 sqrt2/2 = 10 sqrt2
+129852 We can use the Law of Sines, here
AB BC
_____ = _____
sin C sin A
20 BC
_____ = ____
sin 45 sin 30
20 BC
______ = ____
1 / √2 1/ 2
20√2 = 2BC divide both sides by 2
20√2
____ = BC = 10√2
2
