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9p8x2q14/18q=9p8+?

 Mar 23, 2016
 #1
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Simplify the following:
(9×2 p^8 q^14)/(18 q)

9/18 = 9/(9×2) = 1/2:
(2 p^8 q^14)/(2 q)

(2 p^8 q^14)/(2 q) = 2/2×(p^8 q^14)/q = (p^8 q^14)/q:
(p^8 q^14)/q

Combine powers. (p^8 q^14)/q = p^8 q^(14-1):
p^8 q^14-1

14-1 = 13:
Answer: |  p^8 x q^13

 Mar 23, 2016
 #2
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9p^8x2q^14/18q=9p^8+?

 

I have taken th liberty of adding brackets as this is what I think you mean ...

9p^8 x 2q^14/(18q)=9p^8+?

 

 

\(\frac{9p^8*2q^{14}}{18q}=9p^8+Z \qquad find\;Z\\ Z=\frac{9p^8*2q^{14}}{18q}-9p^8\\ Z=\frac{p^8q^{14}}{q}-9p^8\\ Z=p^8q^{13}-9p^8\\ or\\ Z=p^8(q^{13}-9)\)

 Mar 23, 2016

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