Simplify the following:
(9×2 p^8 q^14)/(18 q)
9/18 = 9/(9×2) = 1/2:
(2 p^8 q^14)/(2 q)
(2 p^8 q^14)/(2 q) = 2/2×(p^8 q^14)/q = (p^8 q^14)/q:
(p^8 q^14)/q
Combine powers. (p^8 q^14)/q = p^8 q^(14-1):
p^8 q^14-1
14-1 = 13:
Answer: | p^8 x q^13
9p^8x2q^14/18q=9p^8+?
I have taken th liberty of adding brackets as this is what I think you mean ...
9p^8 x 2q^14/(18q)=9p^8+?
\(\frac{9p^8*2q^{14}}{18q}=9p^8+Z \qquad find\;Z\\ Z=\frac{9p^8*2q^{14}}{18q}-9p^8\\ Z=\frac{p^8q^{14}}{q}-9p^8\\ Z=p^8q^{13}-9p^8\\ or\\ Z=p^8(q^{13}-9)\)