Aarav walks from his house at 9/2 km/hr andreaches his school late by 8 minutes. Next day,

he increases his speed by 1 km/hr and reaches 8

minutes before school time. How far is the school

from his

house?

Guest Apr 28, 2021

#1**+1 **

Call his normal time to reach school = T

And 8 min = 8/60 hr = (2/15) hr

And rate x time = distance....so....equating distances we have

(9/2)(T + 2/15) = (9/2 +1) ( T - 2/15)

(9/2 ) ( T + 2/15) = (11/2) (T - 2/15)

(9/2)T + (9/15) = (11/2)T - 11/15

(11/15) + (9/15) = (11/2) T - (9/2)T

20/15 = T = (4/3) hr

So...the distance is

(9/2) ( 4/3 + 2/15) =

(9/2) ( 22/15) = 33/5 km = 6.6 km

CPhill Apr 28, 2021